A
Anonymous
Guest
OK, gang. the block ('68) is done and the head (OZ2502V) is at the shop now. They are going to CC it for me and once I know what the combustion chamber volume is, I need to be able to tell them how much to mill. I used the compression calculator from the Schjeldahls with these values (bored .020, decked to .010, metal shim gasket on the way so i used .027 has it's compressed value):
Number Of Cylinders 6
Bore Diameter [inches] 3.70
Stroke Length [inches] 3.126
Combustion Chamber Volume [cubic centimeters] 50
Head Gasket Compressed Thickness [inches] .027
Head Gasket Bore Diameter [inches] 3.81
Piston To Deck Clearance [inches] .010
Select Piston Type Dished
Dish/Valve Relief/Dome Volume [positive cubic centimeters] 7
Volumetric Efficiency: 90%
RPM: 5000
Results:
Displacement, [cubic inches] 202
Displacement, [liters] 3.3
Static compression ratio 9.6:1
Cubic Feet per Minute required @ 5000 rpm, [cfm] 263
Estimated Horsepower @ 5000 rpm
Assumes altitude of sealevel, barometric pressure of 14.696 and 60° air supply to carburator 162
How does that all look? Obviously, the combustion chamber size I used is the variable I can change to hit my target of 9.6:1. I used 50 in this calculation to get there. From what I've read, most of the OZ heads run between 54-56...right?
Is there an equation I can use to figure out how much to mill to lower the chamber volume by x? Like:
.010 = 1cc or something?
The "Handbook" says .060 will raise the compression by 1 value. Is that a GOOD general assumption even on the OZ head? The book also states that milling .030 on a '78 head from 60.5 to 54. that means a .030 milling reduced the volume by 6.5 CC's. Does this apply to the OZ head?
Number Of Cylinders 6
Bore Diameter [inches] 3.70
Stroke Length [inches] 3.126
Combustion Chamber Volume [cubic centimeters] 50
Head Gasket Compressed Thickness [inches] .027
Head Gasket Bore Diameter [inches] 3.81
Piston To Deck Clearance [inches] .010
Select Piston Type Dished
Dish/Valve Relief/Dome Volume [positive cubic centimeters] 7
Volumetric Efficiency: 90%
RPM: 5000
Results:
Displacement, [cubic inches] 202
Displacement, [liters] 3.3
Static compression ratio 9.6:1
Cubic Feet per Minute required @ 5000 rpm, [cfm] 263
Estimated Horsepower @ 5000 rpm
Assumes altitude of sealevel, barometric pressure of 14.696 and 60° air supply to carburator 162
How does that all look? Obviously, the combustion chamber size I used is the variable I can change to hit my target of 9.6:1. I used 50 in this calculation to get there. From what I've read, most of the OZ heads run between 54-56...right?
Is there an equation I can use to figure out how much to mill to lower the chamber volume by x? Like:
.010 = 1cc or something?
The "Handbook" says .060 will raise the compression by 1 value. Is that a GOOD general assumption even on the OZ head? The book also states that milling .030 on a '78 head from 60.5 to 54. that means a .030 milling reduced the volume by 6.5 CC's. Does this apply to the OZ head?