For an average of 1, multiply the sum of the nine variables by 362. For 2, multiply by 250. For 3, multiply by 204. For 4, multiply by 228. For 5, multiply by 265. For anywhere in between, use math or make an approximation.
That 20 (averaging 2.222) should be multiplied by 240. 2.222 is a look-up value of about 240 from the values above. 20*240 is 4800.
Hence
65.6*8000 = 109.3 hp
_______4800.
So its closer within the rules of the game. The head is equivalent to a 0.58 ratio valve, and you are bang on that it should be ranked as a 1. Two 27mm valves is really like one good 38 mm number in a 66 mm piston.
Thats about 10% low, I guess.
(I'm tryin not be too defensive

)
What this needs is a tenth term, that of valve lift, or perhaps I should stick with a clarification of the term 'Camshaft Intensity'
What I'm eager to do is have it face-off against a stock computer program like grease_monkey_1966's neat post.
With a little tweeking, and your close scrutiny, we could have a Power Games playoff, X-verses the computer, with your decision final. After all, you've got more qualifications than me. I dig roads for a living, and your the IT man!
Once I've got the charted Hp, the torque curve can be resolved using my former emperical posts. From the past rear wheel dyno information that my Wheels magazines show, I've got a very good way of producing a 12 point graph on my Excel program at work. Did you realise that a power curve is really just a polynomial , y= x2 +2x+x, with a lateral shift and scale factor? I firmly recon that the stuff I've seen on dyno runs may be easily modled from those emperical rules listed here:-
From
http://fordsix.com/forum/viewtopic.php?p=18030&highlight=#18030, posted in Feb 17, 2003
In metrics, the maximum torque in a side valve V8 , in Nm cannot be more than 4 times the Kw figure. A 3619 cc Flat head Ford V8 is at this extreme. A quad cam 3929 cc 1974 LP 400 Lamborghini runs in at 268 kw and something like 385 Nm, so it has a ratio of 1.43 Nm for each Kw.
Our Aussie Mustang based Falcon V8's run around 165 kW and 385 Nm. The ratio is 2.33. My friends 351 Cleveland has 149 kw and 415 Nm..which is 2.79
In imperial SAE, net figures after 1972, a sidevalve Ford may have 2 foot-pounds per horsepower. Say a real 73 hp, not 85 gross, and perhaps only 147 lb-ft, not the claimed 160 or so I think I read somewhere, and rev limit of 3800 rpm or so, peak torque at around 1800 rpm.
An Aussie 1982 351C with 200 horses and 306 lb-ft, 1.53 lb-ft per hp, rev limit 4800 rpm, peak torque at 2800 rpm
A 5.0 HO EFI Mustang engine with 225 hp and 284 lb-ft rates 1.26 lb-ft per hp, Rev limit 5500 rpm or more, peak torque at 3500 rpm
A Lamborghini LP400 is 375 hp and 286 lb-ft, rates in at 0.76 lb-ft per hp. Rev limit 8000 rpm. Peak torque at 5500 rpm
See the pattern? Gain revs, always loose torque proportionaly.
Those figures act as a translational shift of the torque curve. I do understand torque makes power, but if its done the other way around from the alogritum above, the results are more accurate. I will set the 9 factors and calcs up in a Microsoft Works spreadsheet, and scale the torque coefficients based on that info above. Then then I'll set these ground rules in stone and I won't be able to change a thing after its locked in.
The results can be charted against a commercial program if you wish.